Voltage Division
3. How the Voltage Gets Distributed
The key concept here is voltage division. In a series circuit, the total voltage supplied by the power source is divided amongst the resistors. The amount of voltage each resistor "gets" depends on its resistance value. A larger resistor will have a larger voltage drop across it than a smaller resistor.
Think of it like splitting a pizza. If you have a bigger slice, you get more pizza, right? Similarly, a resistor with a higher resistance "takes" a bigger chunk of the total voltage. The distribution isn't necessarily equal; it's proportional to the resistance values. So, if one resistor has twice the resistance of another, it will have twice the voltage drop.
So how can we figure out precisely how much voltage falls across each resistor? We use a little bit of Ohm's Law, which states that Voltage (V) = Current (I) Resistance (R). And some basic math. The voltage across each individual resistor can be found by multiplying the resistance of that resistor by the circuit's current. Because the current is the same throughout, the resistor with the highest resistance will have the highest voltage drop!
The sum of all the voltage drops across each resistor in a series circuit must equal the total voltage supplied by the power source. This is known as Kirchhoffs Voltage Law. It basically states that energy is conserved. The voltage that comes out of the battery is the same amount as the sum of voltage that the resistors absorb. If it doesnt, something is up with your measurements or with your circuit!
The Math Behind the Magic (Ohm's Law in Action)
4. Crunching the Numbers: An Example
Let's say we have a 12V battery connected to two resistors in series: a 4-ohm resistor and a 2-ohm resistor. First, we need to find the total resistance of the circuit, which is simply the sum of the individual resistances: 4 ohms + 2 ohms = 6 ohms. Pretty easy, huh?
Next, we use Ohm's Law (V = IR) to find the current flowing through the circuit. Rearranging the formula, we get I = V/R. So, the current is 12V / 6 ohms = 2 amps. Remember, the current is the same throughout the series circuit.
Now, we can calculate the voltage drop across each resistor. For the 4-ohm resistor, the voltage drop is V = IR = 2 amps 4 ohms = 8V. For the 2-ohm resistor, the voltage drop is V = IR = 2 amps * 2 ohms = 4V.
Notice that the sum of the voltage drops (8V + 4V) equals the total voltage supplied by the battery (12V). Kirchhoff's Voltage Law in action! Also, the 4-ohm resistor (the larger one) has the larger voltage drop. Now you're cooking with gas! Or, you know, electricity.